Question

find the root of 2x^2+45x-47=0

Answer 1

Answer:

2x^2+45x-47

2x^2-2x+47x-47

2x(x-1)+47(x-1).

Step-by-step explanation:

Please mark it as brainlest answer.

Answer 2

2x²+45x-47=0

2x²+47x-2x-47=0

x(2x+47)-1(2x+47)=0

(x-1)(2x+47)=0

x-1=0 and 2x+47=0

x=1 and 2x=-47 => x= -47/2

x= 1, -47/2