Question

find the root of 2xsquare+7x+3=0 by the method of completing square method

Answer 1

Step-by-step explanation:

2x^2-7x=-3

X^2-7x/2=-3/2

X^2-2x1/2x7x/2=-3/2

X^2-2x1/2x7x/2+(7/4)^2=-3/2+(7/4)^2

(X-7/4)^2=-3/2+49/16

(X-7/4)^2=25/16

X-7/4=+or -5/4

x=+5/4+7/4

X=12/4=3

Also

X=-5/4+7/4

2/4=1/2

Hence x=3 and 1/2