Question

find the root of (2z+3)(z+5)+1=0​

Answer 1

Step-by-step explanation:

z

5

+z

4

+z

3

+z

2

+z+1=0

z

3

(z

2

+z+1)+1(z

2

+z+1)=0

(z

3

+1)(z

2

+z+1)=0

(z+1)(z

2

−z+1)(z

2

+z+1)=0

[z=−1][z=w,w

2

]→cube unity cos

6

π

+sin

6

π

z

2

−z+1 never gets a real no solution.

Answer 2

Answer:

roots not real

Step-by-step explanation:

(2z+3)(z+5)+1=0

2z^2+13z+16=0