find the root of 4x²+3x+5=0 by the method of completing the squre
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Answer:
x=-3+✓71i/8 and x=-3-✓71/8
Step-by-step explanation:
4x^2+3x+5=0
root of the equation ax^2+bx+c=0 is
x=-b+-✓b^2-4ac/2a
x=-3+-✓9-80/8
x=-3+-✓71i/8
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