Question

find the root of 5x²-8x+1​

Answer 1

Solution:-

Given,

Quadratic Equation = 5x²-8x+1 in the form of ax²+bx+c = 0

By Dharacharya Formula

$\boxed{\tt{\star\; x = \frac{-b±\sqrt{b²-4ac}}{2a}}}$

Here, a = 5, b = -8 & c = 1

$→\;\Large{\sf{\frac{-(-8)±\sqrt{(-8)²-4×5×1}}{2×5}}}$

$→\;\Large{\sf{\frac{8±\sqrt{64-20}}{10}}}$

$→\;\Large{\sf{\frac{8±\sqrt{44}}{10}}}$

$→\;\Large{\sf{\frac{8±2\sqrt{11}}{10}}}$

$→\;\Large{\sf{\frac{2(4±\sqrt{11})}{10}}}$

$→\;\Large{\sf{\frac{4±\sqrt{11}}{5}}}$

Therefore, The Roots of given Quadratic Equation are

◕➜$\Large{\red{\sf{\frac{4+\sqrt{11}}{5}}}}$ & $\Large{\green{\sf{\frac{4-\sqrt{11}}{5}}}}$

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Answer 2

Answer:

Refer The Attachment ⬆️

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