Question

find the root of equation 2x square _3x+5​

Answer 1

Answer:

Step-by-step explanation:

2 x^2 - 3x + 5 = 0

Where,

a = 2

b = -3

c = 5

[ According to ax^2 + bx + c = 0 , we just compared the equation with this]

Now, we know,

D = b^2 - 4ac

D = (-3)^2 - 4 × 2 × 5

D = 9 - 8 × 5

D = 9 - 40

D = - 31

Now, we know,

If D is less than 0 ( D < 0 ) then no real roots exist.

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