Math, asked by krvinith27, 7 months ago

find the root of equation x^2+5√5x-70=0​

Answers

Answered by Anonymous
6

Answer:

Step-by-step explanation:

x² + 5√5x - 70 = 0

x² + 7√5x - 2√5x - 70 = 0

x ( x + 7√5) - 2√5 ( x + 7√5) = 0

( x + 7√5) ( x - 2√5 ) = 0

( x + 7√5) = 0,

( x - 2√5 ) = 0

x = -7√5, 2√5

i hope it's help you

Answered by archanapradeep010719
0

Step-by-step explanation:

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