Question

find the root of equation x2 -7x+12 =0​

Answer 1

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Your answer is here....

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Answer 2

${x}^{2} - 7x + 12 = 0$

${x }^{2} - 3x - 4x + 12$
$x(x - 3) +4(x - 3)$
$(x + 4) = 0 \\ (x - 3) = 0$
$x = - 4 \\ x = 3$
therefore the two zeros are -4 and 3