Question

find the root of following x²-64=0​

Answer 1

Answer:

+8, -8

Step-by-step explanation:

given equation is x^2-64=0

transpose -64 to rhs it becomes +64

x^2=0+64

x^2=64

apply square root on both sides

√x^2=√64

x=+8, -8

THEREFORE THE ROOTS OF THE EQUATION ARE +8, -8.

I hope you are satisfied by my answer.

Answer 2

Answer:

x = ±8

Step-by-step explanation:

x² - 64 = 0

x² = 64

x = √64

x = √(8×8)

x = ±8

So , root of the equation is ±8

CHECK :-

x² - 64 = 0

x = 8

(8)² - 64 = 0

64 - 64 = 0

0 = 0

Hence, LHS = RHS

So, x = 8