Question

Find the root of quadratic equation x^2-3x-1=0 by factorization

Answer 1

Answer:

Step-by-step explanation:

To find the root by factorisation method of the given equation is not possible.

Answer 2

Answer:

$a {x}^{2} - bx - c = 0$

${x}^{2} - 3x - ( - 1) = 0$

a=1

b=3

c=-1

$x = \frac{ -b ± \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{ - 3± \sqrt{ {3}^{2} - 4 \times 1 \times - 1} }{2 \times 1}$

$x = \frac{ - 3± \sqrt{9 - 4} }{2}$

$x = \frac{ - 3± \sqrt{5} }{2}$

$x = \frac{ - 3±2.236}{2}$

now,

$x1 = \frac{ - 3 - 2.236}{2}$

$x1 = \frac{ - 5.236}{2}$

$x1 = - 2.618$

or,

$x2 = \frac{ - 3 + 2.236}{2}$

$x2 = \frac{ - 0.764}{2}$

$x2 = - 0.382$

so the root of quadratic equation x^2-3x-1=0 is 2.618 or - 0.382