Question

Find the root of quadratic equation x^2-7x+10=0

Answer 1

Answer:

$x {}^{2} - 7x + 10 = 0$

$x {}^{2} - (5 + 2)x + 10 = 0$

$x {}^{2} - 5x - 2x + 10 = 0$

$x(x - 5) - 2(x - 5) = 0$

$(x - 2)(x - 5) = 0$

$either$

$x = 2$

$or$

$x = 5$

Answer 2

Answer:

$x {}^{2} - 7x + 10 = 0 \\ = {x}^{2} - 5x - 2x + 10 = 0 \\ = x(x - 5) - 2(x - 5) = 0 \\ = (x - 5)(x - 2) = 0 \\ x = 5 \: \: and \: \: 2$

Hey! Mate Here is your solution. Thanks