Question

find the root of quadratic equation x2+x-6=0,by factorization method​

Answer 1

Solution

Given =》

▪︎ x²+x-6=0

Need to find =》

Roots

Explanation =》

▪︎ x²+x-6=0

= x²+(3-2)x-6=0

= x²+3x-2x-6=0

= x( x+3)-2(x+3)=0

= (x+3)=0, (x-2)=0

= x= -3, x=2

Hence, Roots are 3 and 2

Answer 2

Answer:

2&-3

Step-by-step explanation:

x^2+(3-2)x-6=0

x^2+3x-2x-6=0

x(x+3)-2(x+3) =0

(x-2)(x+3) =0

thus x= 2 and -3

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