find the root of quadratic equation6x2 -x-2
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Answered by
1
Step-by-step explanation:
Given 6x^2-x-2=0 6x^2+3x-4x-2=0
3x(2x+1)-2(2x+1)=0
(3x-2)(2x+1)=0
therfore 3x=2 or 2x=-1/2
therfore x=2/3 or -1/4
Answered by
2
Answer:
6x^2 - x - 2 = 0
6x^2 - 4x + 3x - 2 = 0
2x(3x - 2) + 1(3x-2) = 0
(2x+1)(3x-2)=0
x = -1/2 , 2/3
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