find the root of quartic equation 3x square- 2x√6-2 =O.. ans fast.pls do step by step
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3x² – 2√6 x – 2 = 0
a = 3, b = – 2√6, c = – 2
D = √b² – 4ac
D = √ ( – 2√6 )² – 4 ( 3 ) ( – 2 )
D = √ 24 + 24
D = √48
D = 4√3
x = ( – b ± D ) / 2a
x = ( 2√6 ± 4√3 ) / 2×3
x = (√6 ± 2√3 ) / 3
x = (√6 + 2√3 ) / 3
or
x = (√6 – 2√3 ) / 3
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