Question

find the root of :
${6x }^{2} - 13x + 6 = 0$

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Answer 1

Answer:

the two roots of the equation is 3/2 and 2/3

Step-by-step explanation:

6x^2-13x+6=0

6x^2-(9+4)x+6=0

6x^2-9x-4x+6=0

3x(2x-3)-2(2x-3)=0

(2x-3)(3x-2)=0

either, or,

2x-3=0 3x-2=0

2x=3 3x=2

x=3/2 x=2/3

Answer 2

Answer :

X = 2/3, 3/2

Therefore, the roots of 6x^2 - 13x + 6 = 0 are 2/3, 3/2