Question

Find the root of the equation 2x2 -2V2 x +1=0
pls be fast​

Answer 1

Answer:

${2x}^{2} - 2 \sqrt{2} x + 1 = 0 \\ \sqrt{2} \sqrt{2} {x}^{2} - \sqrt{2} x - \sqrt{2} x + 1 = 0 \\ \sqrt{2} x( \sqrt{2} x - 1) - 1( \sqrt{2} x - 1) = 0 \\ ( \sqrt{2} x - 1)( \sqrt{2} x - 1) = 0 \\ {( \sqrt{2}x - 1) }^{2} = 0 \\ \sqrt{2} x - 1 = 0 \\ \sqrt{2} x = 1 \\ x = \frac{1}{ \sqrt{2} } \\ x = \frac{ \sqrt{2} }{2}$