Find the root of the equation 3x^2 -10x-8=0
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3x^2-10x-8
(×-24)(+-10)
-12and2are numbers
3x^2-12x+2x-8
3x(x-4)+2(x-4)
(3x+2)(x-4)
(3x+2)=0
x=-2/3 x=4
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