find the root of the equation 3x²-2√6+2=0
Answers
Answered by
1
Step-by-step explanation:
Q.
Find the root of the equation 3x² + 2√6 + 2 = 0
.
Solution -
In the standard form of quadratic equation (ax² + bx + c = 0), here
a = 3
b = -2√6
c = 2
.
Using the discriminant, we will find that roots of equation are real or imaginary.
Discriminant = b² - 4ac
= (-2√6)² - 4(3)(2)
= 24 - 24
= 0
Because Discriminant = 0, so roots will be real and equal.
.
Now using the formula for roots of quadratic equation -
Hence the root of this equation is √2/√3
Note :-
If Discriminant (b² - 4ac) is,
- D > 0, roots are real and unequal
- D = 0, roots are real and equal
- D < 0, rots are unreal (imaginary)
A quadratic equation have only two zeroes
.
Relation between coefficient and zeroes (roots) of equation -
Sum of zeroes = -b/a
product of zeroes = c/a
hope it helps.
Similar questions
Hindi,
3 hours ago
Accountancy,
3 hours ago
History,
5 hours ago
Chemistry,
7 months ago
Science,
7 months ago