Find the root of the equation 4x + 3 = 2(x_4)
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Answered by
0
Answer:
Solution to Question ID 610089
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Let the roots be a,a,b,b
we have a+a+b+b=−4 and a
2
b
2
=9
⇒a+b=−2 and ab=±3
Case I: ab=3
(a−b)
2
=(a+b)
2
−4ab
(a−b)
2
=4−12=−8 which is not possible. Hence ab
=3
Case II: ab=−3
(a−b)
2
=(a+b)
2
−4ab
(a−b)
2
=4−4(−3)=4+12=16
(a−b)=±4
a+b=−2
a−b=4 or a−b=−4
⇒2a=2 or 2a=−6
⇒a=1 or a=−3
⇒b=−3 or b=1
Hence we get −3,−3,1,1 as roots of given equation
Answered by
0
Answer:
x is - 11/2
Step-by-step explanation:
4x + 3 = 2(x - 4)
4x + 3 = 2x - 8
4x - 2x = - 8 - 3
2x = - 11
x - -11/2
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