Question

find the root of the equation 5x^2-9=0​

Answer 1

Answer:

roots are=(-3√5)/5 and (3√5)/5

Step-by-step explanation:

f it’s 5x^2 -9 =0

Then we can approach even this way….

(√5x)^2 -3 ^2 =0

Now according to trigonometric identity a^2-b^2= (a+b) (a-b) so the same way here

a= (√5x) and b= 3 so

(√5 x+3)( √5x-3)=0

(√5x +3)=0 or (√5x-3)=0

{So x= -3/√5or x=3/√5 }

Further if u would rationalise then

x= (-3√5)/5 or x=(3√5)/5

Answer 2

$\sqrt{ {(5x)}^{2} - 9 = 0} \\ \\ \implies \: \sqrt { {(5x)}^{2} - {(3)}^{2} = {0}^{2} } \\ \\ \implies \: \sqrt{ {(5x -3 = 0)}^{2} } \\ \\ = 5x - 3 = 0 \\ \\ = > 5x = 3 \\ \\ x = \frac{3}{5}$

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