Question

find the root of the equation 6y^2-y-2= 0 using quadratic equation​

Answer 1

Answer:

Roots are 2 / 3 or - 1 / 2.

Step-by-step explanation:

6y² - y - 2 = 0

=> 6y² - 4y + 3y - 2 = 0

=> 2y ( 3y - 2 ) + 1 ( 3y - 2 ) = 0

=> ( 3y - 2 ) ( 2y + 1 ) = 0

=> 3y - 2 = 0 or 2y + 1 = 0

=> 3y = 2 or 2y = - 1

=> y = 2 / 3 or y = - 1 / 2

So,

Roots are 2 / 3 or - 1 / 2.

Answer 2

Answer:

Hello frnd!!

Step-by-step explanation:

6y²-y-2=0

We will solve this Quadratic equation by the method of Splitting the middle term :

We need to multiply 6×(-2) = -12 and factorise it such that the addition is -1 and those factors will be -4 and 3.

6y²-4y+3y-2 = 0

2y(3y-2) + 1(3y-2) = 0

Pick out the common...

(2y+1) (3y-2) = 0

(2y+1) = 0 , (3y-2) = 0

y = -1/2 , y = 2/3

Therefore, the solutions (roots) will be -1/2 and 2/3.

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