Question

find the root of the equation by using quadratic formula :xsquare +x-(a+2)(a+1)=0​

Answer 1

Step-by-step explanation:

Given :-

• quadratic equation : x²+x-(a+1)(a+2)=0

To Find :-

• find the root of the equation

Solution :-

=> x²-(a+1)x+(a+2)x-(a+1)(a+2)=0

=> x[x-(a+1)]+(a+2)[x-(a+1)]=0

=> [x-(a+1)][x+(a+2)]=0

=> x = (a+1) and x = -(a+2)

Hence x =(a+1) Or x = -(a+2) are two roots of given quadratic equation.

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