Question

find the root of the equation
$2 \sqrt{3}{x}^{2} - 5x + \sqrt{3}$
by quadratic formula it's urgent
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Answer 1

$\Large\underline\mathbb\blue{ANSWER}$

$\: \: \: \: \: \: \: \: \: \: \: \tt{2 \sqrt{3}{x}^{2} - 5x + \sqrt{3} = 0} \\ \implies \tt{2 \sqrt{3}{x}^{2} - 2x - 3x+ \sqrt{3} = 0} \\ \implies \tt{2x( \sqrt{3} x - 1) - \sqrt{3} ( \sqrt{3} x - 1) = 0} \\ \implies \tt \purple{{(2x - \sqrt{3} )( \sqrt{3} x - 1)}}$

The Zeroes so obtained are:

$\boxed{\pink{x = \frac{ \sqrt{3} }{2} }}$

$\boxed{\pink{x = \frac{ 1 }{ \sqrt{3} } }}$

$\tt{hope \: its \: helpful}$