Find the root of the equation..
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Answered by
2
Heya brother,
Here is your answer,
Given eq : x - 1/x = 3
Taking LCM,
=> x² - 1 = 3x
=> x² - 3x - 1 = 0
Now,
=> x = [-b ± √(b² - 4ac)]/2a
Since, b = -3, a = 1, c = -1
Therefore,
=> x = [3 ± √(9 - 4(1)(-1))]/2
=> x = [3 ± √13]/2
Therefore,
The values of x are,
=> x = [3 + √13]/2 or x = [3 - √13]/2
Hope it helps you brother.
Thank you.
Here is your answer,
Given eq : x - 1/x = 3
Taking LCM,
=> x² - 1 = 3x
=> x² - 3x - 1 = 0
Now,
=> x = [-b ± √(b² - 4ac)]/2a
Since, b = -3, a = 1, c = -1
Therefore,
=> x = [3 ± √(9 - 4(1)(-1))]/2
=> x = [3 ± √13]/2
Therefore,
The values of x are,
=> x = [3 + √13]/2 or x = [3 - √13]/2
Hope it helps you brother.
Thank you.
YASH3100:
it's correct brother :)
Answered by
3
Hello!!
see this answer..
Hope it helps you.
☺☺
see this answer..
Hope it helps you.
☺☺
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