Find the root of the equation x^3-2x-5= 0 by Bisection method correct up to three decimal places?
Answers
Given : x³ - 2x - 5 = 0
To find : root of the equation by Bisection method correct up to three decimal places
Solution:
x³ - 2x - 5 = 0
x = 1 => 1 - 2 - 5 = - 6
x = 2 => 8 - 4 - 5 = - 1
x = 3 => 27 - 6 - 5 = 16
0 lies between -1 & 16
Hence x lies between 2 & 3
(2 + 3)/2 = 2.5
x = 2.5 => x³ - 2x - 5 = 5.625
0 lies between -1 & 5.625
=> x lies between 2 & 2.5
(2 + 2.5)/2 = 2.25
x = 2.25 => x³ - 2x - 5 = 1.89
0 lies between -1 & 1.89
=> x lies between 2 & 2.25
=> x = 2.125 => x³ - 2x - 5 = 0.34
0 lies between -1 & 0.34
=> x lies between 2 * 2.125
=> x = 2.0625 => x³ - 2x - 5 = -0.35
0 lies between -0.35 & 0.34
=> x lies between 2.0625 & 2.125
x = 2.09375 => x³ - 2x - 5 = -0.0089 ≈ 0
x = 2.094 up to three decimal places
x = 2.094
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a+b+c=3 a^2+b^2+c^2=6 1/a+1/b+1/c=1 find values of a , b and c
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Answer:
x≓2.094551504
Step-by-step explanation:
x≓2.094551504