Find the root of the equations 4(y+3)= 7y+ 1/2
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Answered by
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4y+12=7y+1/2
12-1/2 = 7y-4y
(24-1)/2 = 3y
23/2 = 3y
23/6 = y
12-1/2 = 7y-4y
(24-1)/2 = 3y
23/2 = 3y
23/6 = y
shreyapriya:
It is 4y+3
Is the question correct?
Myn
My question is correct
but u have taken an
as 13
ooops sorry just a second wil change it
Answered by
0
4(y+3)=7y+1/2
4y+12=7y+1/2
4y-7y = 1/2 - 12
-3y=(1-24)2
-3y=-23/2
y=23/6
4y+12=7y+1/2
4y-7y = 1/2 - 12
-3y=(1-24)2
-3y=-23/2
y=23/6
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