Question

Find the root of the following equation by factorisation (P + q and p x q method) is equal to x square - 10x + 21 =0
Hint. ax2+bx+c=0 where p+q=b, p x q is equal to a multiply c

Answer 1

$\fontsize{18}{10}{\textup{\textbf{The required roots are 3 and 7}}}$

Step-by-step explanation:

The given equation

x^2-10x+21

=>x^2-(7+3)x+7*3=0 , here p=7, q=3

=>(x-7)(x-3)=0

=>x=7,3

So the roots are 3,7