Question

Find the root of the following polynomial (i)3x-2(ii)6x-5​

Answer 1

$\huge \sf1) \: \: 3x - 2 \\ \\ \tt= > 3x - 2 = 0 \\ \tt = > \: \: \: \: \: \: \: \: 3x = 2 \\ \tt = > \: \: \: \: \: \: \: \: \: \: x = \red{ \frac{2}{3} }$

And,

$\sf \huge2) \: \: \: 6x - 5 \\ \\ \tt = > 6x - 5 = 0 \\ \tt = > \: \: \: \: \: \: \: \: 6x = 5 \\ \tt = > \: \: \: \: \: \: \: \: \: \: x = \red{ \frac{5}{6} }$

Hence,

• Root (or Zeroes) of 3x - 2 is $\bf\frac{2}{3}$.

• Root (or Zeroes) of 6x - 5 is $\bf\frac{5}{6}$.

☆Extra Information☆

• Roots (or Zeroes) are certain values of x in an equation p(x) which can make the whole equation equal to zero(0).
• These are real numbers.