Question

find the root of the following
quadratic equation by
factorization
2x²+x-300=0​

Answer 1

Answer:

x= -25/2 , 12

Step-by-step explanation:

first we multiply the last and first terms coefficients.

so, -300*2= -600

now, we middle term split to get the answer as +1

25 and -24

there fore the terms will be 2x^2 -24x +25x - 300

now we take them commons terms out

2x(x-12) + 25(x-12) = 0

therefore, x=-25/2 and x=12

Answer 2

Answer:

2x²+x-300=0

➙ 2x²+(25 - 24) x-300=0

➙ 2x²+25x - 24x-300=0

➙ x ( 2x + 25) - 12 ( 2x + 25) = 0

➙ ( 2x + 25) (x - 12) = 0

So either ( 2x + 25) = 0 or (x-12) =0

Now ( 2x + 25) = 0 gives x = - 25/2

Again (x - 12) = 0 gives x = 12

Hence the required solution is

x = - 25/2, 12

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