Question

find the root of the following quadratic equation
${x}^{2} -3 \sqrt{5}x + 10 = 0$

Answer 1

we can find roots by splitting middle terms is such a way
that sum equals to -3√5 (-2√5& -√5)
and product equals= 10({2√5}x√5)

x^2-2√5x-√5x+10=0
x(x-2√5) -√5(x-2√5)=0
(x-√5)(x-2√5)=0

x= √5&2√5