Question

find the root of the following quradatic equation by factorisation x2+2√2x+2=0​

Answer 1

$\mathtt{x²+2√2x+2 = 0}$

$\mathtt{x²+√2x+√2x+2 = 0}$

$\mathtt{x(x+√2)+√2(x+√2) = 0}$

$\mathtt{(x+√2)(x+√2) = 0}$

$\mathtt{(x+√2)= 0 \;\;\;or\;\;\;(x+√2)=0}$

$\mathtt{x=-√2 \;\;\; or \;\;\;x=-√2}$

$\mathtt{Hence, \; x=√2 \; \& \; x=√2 \; is \; the \; root \; of \; x²+2√2x+2=0}$