Question

find the root of the given quadratic equation by factorisation method

√2 x² + 7x + 5√2= 0

Answer 1

↑ Here is your answer ↓
_____________________________________________________________
_____________________________________________________________

Given polynomial,

$\sqrt 2 x^2 + 7x + 5 \sqrt2 = 0$

$S = 7$

$P = \sqrt 2 * 5 \sqrt 2 = 10$

∴ Required numbers are 2 and 5

$\sqrt2 x^2 + 2x + 5x + 5 \sqrt 2 = 0$

$\sqrt 2 x(x + \sqrt 2) + 5(x + \sqrt 2 ) = 0$

$(\sqrt 2 x + 5)(x+ \sqrt 2) = 0$

So,

$x = -5/ \sqrt 2$

$x = - \sqrt 2$

Answer 2

√2x^2+7x+5√2=0

√2x^2+2x+5x+5√2=0

√2x(x+√2)+5(x+√2)=0

(√2x+5)(x+√2)=0

(√2x+5)=0 (x+√2)=0

√2x+5=0. x+√2=0

√2x=-5. x= -√2

x= -5/√2