Question

Find the root of the given question:-

$\colon\implies{\sf{ 2x^2 + 3x - 90 = 0 }}$​

Answer 1

Answer:

Hii,

Step-by-step explanation:

Hope the attachment will help you..

# XxLovingBoyxX ❤️

Answer 2

Given equation :-

$\colon\implies{\sf{ 2x^2 + 3x - 90 = 0 }}$

• We have to find the Discriminant of this equation by using the formula:-

$:\implies\underline\purple{\boxed{\sf D = b²-4ac}}$

$\implies\sf D = ( 3) ^{2} - 4(2)( -90) \\ \\ \implies\sf D = 9 + 720 =729$

• Since, D>0 hence, this equation will have distinct and real roots.

Formula to be applied now is as follows:-

$\implies\underline\pink{\boxed{\sf x = \dfrac{-b±√D}{2a}}}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀

$\\ \colon\implies{\underline{\boxed{\sf{ x = \dfrac{ -b \pm \sqrt{ b^2 - 4ac} }{2a} }}}} \\ \\ \\ \colon\implies{\sf{ x = \dfrac{ -3 \pm \sqrt{ 3^2 - 4 \times 2 \times (-90)} }{2 \times 2} }} \\ \\ \\ \colon\implies{\sf{ x = \dfrac{ -3 \pm \sqrt{ 9 +720} }{4} }} \\ \\ \\ \colon\implies{\sf{ x = \dfrac{ -3 \pm \sqrt{ 729} }{4} }} \\ \\ \\ \colon\implies{\sf{ x = \dfrac{ -3 \pm 27 }{4} }} \\ \\ \\ \colon\implies{\sf{ x = \dfrac{ -3 + 27 }{4} \ and \ \dfrac{-3-27}{4} }} \\ \\ \\ \colon\implies{\sf{ x = \dfrac{ 24 }{4} \ and \ \dfrac{-30}{4} }} \\ \\ \\ \colon\implies{\underline{\boxed{\sf\red{ x = 6 \ and \ -7.5 }}}}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀