Question

find the root of the quadratic equation 2x^2-2root6x+3=0​

Answer 1

Answer:

What are the places in the millions period? *

Answer 2

$\color{red} \huge \bold{Answer:}$

$\bold{Using \:middle \: term\: method:}$

$\bold{=>2x²-2√6x+3=0}$

$\bold{ = > 2x²-√6x-√6x+3=0}$

$=>√2x(√2x-√3)- \\ √3(√2x-√3)=0$

$\bold{=>(√2x-√3)(√2x-√3)=0}$

$\bold{=>√2x-√3=0 =>x = \frac{ \sqrt{3} }{2} }$

$\bold{Similarly\: another\: root \: also \: x=√3/2}$

$\bold{Roots \: of \: quadratic \: equation: }$

$= > 2x²-2√6x+3=0 \\ \: are \: √3/2 \: and \: √3/2.$