Question

find the root of the quadratic equation
2x²- x-6=0​

Answer 1

Step-by-step explanation:

The given quadratic equation is

2x

2

+x−6=0

⇒2x

2

+4x−3x−6=0

⇒2x(x+2)−3(x+2)=0

⇒(2x−3)(x+2)=0

⇒x=−2,

2

3

Answer 2

Answer:

x = 2 and -3/2

Step-by-step explanation:

==: 2x² - x - 6 = 0

==: 2x² - 4x + 3x - 6 = 0

==: 2x (x - 2) + 3 (x - 2) = 0

==: (x - 2) (2x + 3) = 0

==: x = 2 and -3/2

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