Question

find the root of the quadratic equation 2xsq.+x-528=0

Answer 1

to find the root of the equation
we will use the quadratic equation
first we would find b²-4ac
=1+4224
=4225
=(65)²
root=-b+65/2a=-1+65/4=16
other root=-b-65/2a=-1-65/4==-16.5

Answer 2

$\blue{Hello \: Friends \: }$

$\bold{Given \: quadratic \: equation}$

$\bold{2x {}^{2} + x - 528 = 0}$

Comparing the given quadratic equation with,,,

$\bold{ax {}^{2} + bx + c = 0}$

∴
$\bold{a \: = 2 \: \: .b = 1 \: \: \: \: .c = - 528}$

NOW,

$\bold{b {}^{2} - 4ac \: = 1 {}^{2} - 4 \times 2 \times - 528 }$
$\bold{b {}^{2} - 4ac \: = 4225 }$

$\orange{we \: know \: that \: ...}$

$x = \frac{ - b \: + - \sqrt{b {}^{2} - 4ac } }{2a}$

$x \: = \frac{ - 1 + - \sqrt{4225} }{2 \times 2} \\ \\ x = \frac{ - 1 + - 65}{4} \\ \\ x = \frac{ - 1 + 65}{4} \: \: or \: x = \frac{ - 1 - 65}{4}$

$x = \frac{64}{4} \: \: or \: \: x = \frac{ - 66}{4} \\ \\ x = 16 \: \: \: \: \: or \: x = \frac{ - 33}{2} = - 16.5$

$\boxed{x = 16} \: \: \: or \: \: \: \boxed{x = \frac{ - 33}{2} = - 16.5}$

$\pink{Thanks \: for \: your \: question \: } \\ \\ \boxed{Be \: Brainly}$