Math, asked by ramyamaddeboina, 11 months ago

Find the root of the quadratic equation
√2xsquare+7×+5√2=0​

Answers

Answered by zoya12515
3

Step-by-step explanation:

here is your answer and once try to solve it yourself

Attachments:
Answered by sanketj
1

 \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2}  = 0 \\  \sqrt{2}  {x}^{2}  + 2x + 5x +  5\sqrt{2}  = 0 \\  \sqrt{2} x(x +  \sqrt{2} ) + 5(x  + \sqrt{2} ) = 0 \\ ( \sqrt{2} x + 5)(x +  \sqrt{2} ) = 0 \\  \\  \sqrt{2} x + 5 = 0 \:  \:  \:  \:  \:  \:  \:  \: or \:  \:  \:  \:  \:  \: x +  \sqrt{2}  = 0 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   x =  \frac{ - 5}{ \sqrt{2} }  \:  \:  \: or \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  x =  -  \sqrt{2}

Hence, the roots of the given quadratic equation are -5/2 and -2

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