Question

find the root of the quadratic equation 3x^2 - 2√6x +2 =0

Answer 1

the roots of the equation are root 3/root 2 and root 3/root 2

Answer 2

$3x^2 - 2\sqrt{6}x + 2 = 0$

$b^2 - 4ac = (-2 \sqrt{6})^2 - 4(3)(2)$

$= 24 - 24$

$= 0$

Now use quadratic formula!

$\frac{-b + \sqrt{b^2 - 4ac} }{2a}$

$= \frac{2 \sqrt6 + 0}{6}$

$= \frac{\sqrt6}{3}$