Question

Find the root of the quadratic equation 5x^2-2√10x+2=0

Answer 1

Answer:

the root is real and equal

Answer 2

Answer:

Step-by-step explanation:

When comparing to the standard form ax^2+bx+c=0, we have,

a=5

b=-2√10

c=2

b^2-4ac = (-2√10)^2-4*5*2)= D

= 4*10-40

=40-40

=0

As D = 0,the equation will have two equal roots.

x=-b+_√b^2-4ac/2a

x=-(-2√10)+_√0/2a

x= 2√10 / 2*5

x= 2√10/10

x=2/√10

Therefore, the two equal roots are 2/√10 and 2/√10