Question

find the root of the quadratic equation by the prime factorization 3√2x^2 -5x -√2​

Answer 1

Hello Friend

Here is your answer below,,

$3 \sqrt{2} x {}^{2} - 5x - \sqrt{2} \\ = > 3 \sqrt{2} x {}^{2} - 5x + \sqrt{2} = 0 \\ = > 3 \sqrt{2} x {}^{2} - 3x - 2x + \sqrt{2} = 0 \\ = > 3x( \sqrt{2} x - 1) - \sqrt{2} ( \sqrt{2} x - 1) = 0 \\ = > (3x - \sqrt{2} )( \sqrt{2} x - 1) = 0 \\ = > 3x - \sqrt{2} = 0 \\ = > 3x = \sqrt{2} \\ = > x = \frac{ \sqrt{2} }{3} \\ or \\ = > \sqrt{2} x - 1 = 0 \\ = > \sqrt{2} x = 1 \\ = > x = \frac{1}{ \sqrt{2} }$

Hello Friend in your question is last term sign will be plus if it will be not plus then it can't be factories,

I hope that helps you