Question

find the root of the quadratic equation, if they exist applying the quadratic formula 2x^2-7x+3=0​

Answer 1

Step-by-step explanation:

${:}\longrightarrow$

${2x}^{2} - 7x + 3 = 0 \\ = > {2x}^{2} - 6x - x + 3 = 0 \\ = > 2x(x - 3) - 1(x - 3) \\ = > (2x - 1)(x - 3) \\ = > (2x - 1) = 0 \: \: or \: \: (x - 3) = 0 \\ = > x = \frac{1}{2} \: \: or \: x = 3$

${:}\longrightarrow$${\underline{\boxed{\bf{x={\frac{1 }{2}}\:,3}}}}$

Answer 2

Answer:

a = 2, b = -7 and c = 3

Quadratic Formula = (-b ± √b² - 4ac)/2a

-(-7) ± {√(-7)² - 4(2)(3)}/2(2)

(7 ± √49 - 24)/4

(7 ± √25)/4

(7± 5)/4

x = 7 + 5/4. and x = 7 - 5/4

x = 3 and x = 1/2

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