Question

find the root of the quadratic equation :
$2x^{2} + (k - 6)x - 3k = 0 \\ if \: x = - \frac{k}{2} |$
explain the multiplication perfectly!​

Answer 1

Answer:

Correct option is

A

True

Substitute x=2−k in the quadratic equation 2x2+(k−6)x−3k=0

2(2−k)2+(k−6)(2−k)−3k

=2k2−2k2+3k−3k

=0

Thus, 2−k is a root of the equation.