Question

find the root of the quadratic equation x^2+7x+12=o​

Answer 1

Answer:

Here we have #x^2-7x+12=0# i.e. #a=1#, #b=-7# and #c=12#

and #x=(-(-7)+-sqrt((-7)^2-4*1*12))/(2*1)#

= #(7+-sqrt(49-48))/2#

= #(7+-sqrt1)/2#

= #(7+-1)/2#

Answer 2

Answer:

x = -3 / -14

Step-by-step explanation:

${x}^{2} + 7x + 12 = 0 \\ = > {x } ^{2} + 3x + 4x + 12 = 0 \\ = > x(x + 3) + 4(x + 3) = 0 \\ = > (x + 3)(x + 4) = 0 \\ = > (x + 3) = 0 \: \: and \: (x + 4) = 0 \\ = > x = - 3 \: or \: - 4$