find the root of the quadratic equation x^2+7x+12=o
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Answered by
1
Answer:
Here we have #x^2-7x+12=0# i.e. #a=1#, #b=-7# and #c=12#
and #x=(-(-7)+-sqrt((-7)^2-4*1*12))/(2*1)#
= #(7+-sqrt(49-48))/2#
= #(7+-sqrt1)/2#
= #(7+-1)/2#
Answered by
1
Answer:
x = -3 / -14
Step-by-step explanation:
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