Math, asked by aathisri, 10 months ago

find the root of the quadratic equation x^2+7x+12=o​

Answers

Answered by cskooo7
1

Answer:

Here we have #x^2-7x+12=0# i.e. #a=1#, #b=-7# and #c=12#

and #x=(-(-7)+-sqrt((-7)^2-4*1*12))/(2*1)#

= #(7+-sqrt(49-48))/2#

= #(7+-sqrt1)/2#

= #(7+-1)/2#

Answered by Anonymous
1

Answer:

x = -3 / -14

Step-by-step explanation:

 {x}^{2}  + 7x + 12 = 0 \\   =  >  {x } ^{2}  + 3x + 4x + 12 = 0  \\  =  > x(x + 3) + 4(x + 3) = 0 \\  =  > (x + 3)(x + 4) = 0 \\  =  > (x + 3) = 0 \:  \: and \: (x + 4) = 0 \\  =  > x =  - 3 \: or \:  - 4

Similar questions