Question

find the root of the quadratic equations √3x^2+6 =9​

Answer 1

Step-by-step explanation:

√3x^2 +6=9

so √3x^2+6-9=0

a=√3

b=6

c=-9

D=b^2-4ac

=(6)^2-4x√3x-9

=36-36√3

=36(1-√3)

Answer 2

Answer:

$\sqrt{3} {x}^{2} = 3 \\ {x}^{2} = {3}^{1 \div 2} \\ x = {3}^{1 \div 4}$