Question

find the root of this equation

Answer 1

Answer to your question

Answer 2

X+3/x+2-3x-7/2x-3=0

X+3(2x-3)-3x-7(x+2)/(x+2)(2x-3)=0

Simplify it you will get the quadratic

eqaution

X2+10x+23=0

Apply dharacharya we get

X=‌underroot2-5and

X= -(5+underoot2)