Question

find the root of this question in quardratic formula​

Answer 1

Answer:

hope this will help you

Answer 2

Answer:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ = > \frac{11 + - \sqrt{ {( - 11)}^{2} - 4(4)(6) } }{8} \\ = > \frac{11 + - \sqrt{121 - 96} }{8} \\ = > x = \frac{11 + - \sqrt{25} }{8} \\ = > \frac{11 + 5}{8} \: and \: x = \frac{11 - 5}{8} \\ = > \: x = 2 \: and \: x = \frac{3}{4} \\ hope \: it \: helps \: you...$