Math, asked by mohammedfayas007, 7 months ago

find the root of x^2+2√2x-6=0

Answers

Answered by brainlyaryan12

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$\Large{x^2+2\sqrt{2}x-6}$

➡️ $x^2+3\sqrt{2}x-\sqrt{2}x-6$

➡️ $x(x-\sqrt{2})+3\sqrt{2}(x-\sqrt{2})$

➡️ $(x-\sqrt{2})(x+3\sqrt{2})$

First Root ---

➡️ $\huge\orange{\fbox{\pink{x-\sqrt{2}}}}$

Second Root---

➡️ $\huge\orange{\fbox{\pink{x+3\sqrt{2}}}}$

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