Math, asked by ayush3333bhardwaj, 10 months ago

find the root of (x+3)(x+2)=0​

Answers

Answered by Anonymous
4

Answer:

heya mate... :)

(x+3) (x+2) = 0

=> x^2 + 2x + 3x + 6 = 0

=> x^2 + 5x + 6 = 0

=> x^2 + (3+2)x + 6 = 0

=> x^2 + 3x + 2x + 6 = 0

=> x (x+3) + 2 (x+3) = 0

=> (x+3) (x+2) = 0

So, two roots are :

x + 3 = 0

=> x = (-3)

Or, x + 2 = 0

=> x = (-2)

hope it helps u

pls do mark as brainliest if it's worthy

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