find the root of (x+3)(x+2)=0
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Answer:
heya mate... :)
(x+3) (x+2) = 0
=> x^2 + 2x + 3x + 6 = 0
=> x^2 + 5x + 6 = 0
=> x^2 + (3+2)x + 6 = 0
=> x^2 + 3x + 2x + 6 = 0
=> x (x+3) + 2 (x+3) = 0
=> (x+3) (x+2) = 0
So, two roots are :
x + 3 = 0
=> x = (-3)
Or, x + 2 = 0
=> x = (-2)
hope it helps u ♥
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