Question

find the root of x²-2x(m²-1)=0​

Answer 1

Step-by-step explanation:

${x}^{2} - 2x( {m}^{2} - 1) = 0$

$x(x - 2( {m}^{2} - 1)) = 0$

That implies,

$x = 0 \: and \: x = 2( {m}^{2} - 1)$

Answer 2

Hii

Here is your answer -

x²-2x(m²-1)=0​

x(x -2(m²-1)=0​

That implies,

x=0 and x=2(m²-1)