Question

Find the root of x2
-4x-8 =0 by the method of completing square.

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\implies {x}^{2} - 4x - 8 = 0 \\ \implies{x}^{2} - 2 \times 2 \times x + {2}^{2} - {2}^{2} - 8 = 0 \\\implies {(x - 2)}^{2} - {2}^{2} - 8 = 0 \\ \implies{(x - 2)}^{2} - 4 - 8 = 0 \\ \implies {(x - 2)}^{2} - 12 = 0 \\ \implies {(x - 2)}^{2} = 12 \\\implies x - 2 = \sqrt{12} \\ \implies \boxed{\bold\blue{x = 2 + \sqrt{12} \:, \:2 - \sqrt{12}}}$